1.5x^2-3.5=0

Solution for 1.5x^2-3.5=0 equation:

1.5x^2-3.5=0

a = 1.5; b = 0; c = -3.5;
Δ = b2-4ac
Δ = 02-4·1.5·(-3.5)
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{21}}{2*1.5}=\frac{0-\sqrt{21}}{3}
=-\frac{\sqrt{}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{21}}{2*1.5}=\frac{0+\sqrt{21}}{3}
=\frac{\sqrt{}}{3}
$